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Select the correct answer.
You are a contractor who is installing a new bathroom floor with square tiles. The dimensions of the rectangular bathroom
floor are 12 feet long and 8 feet wide. If each tile is 16 square Inches and 8 tiles cost $15, how much will the tiles for the
bathroom floor cost?

Respuesta :

Answer:

The cost of the tiles for the bathroom is $1620.

Step-by-step explanation:

To solve this problem, first we have to find the area of the rectangular bathroom, but before that, we should transform each dimension from feet to inches, because the are of each tile is in inches.

We know that 1 ft is equal to 12 inches. So, 12 feet and 8 feet would be

[tex]12ft\frac{12in}{1ft}=144in^{2}\\ \\8ft\frac{12in}{1ft}=96in^{2}[/tex]

So, the area of the bathroom (in inches) is

[tex]A_{bath}=(width)(length)=144(96)=13824 in^{2}[/tex]

Now, we have to divide the total area of the bathroom by the area of each tile, such quotient will give us the total number of tiles we need

[tex]\frac{13824in^{2} }{16in^{2} }=864 \ tiles[/tex]

So, we need 864 tiles. If 8 tiles cost $15, how much would cost the total 864 tiles, we apply the rule of three

[tex]x=864 \ tiles \ \frac{\$15}{8tiles}=\$1620[/tex]

Therefore, the cost of the tiles for the bathroom is $1620.