Answer:
88 m/s
Explanation:
To solve the problem, we can use the following SUVAT equation:
[tex]v^2-u^2=2ad[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
d is the distance covered
For the car in this problem, we have
d = 484 m is the stopping distance
v = 0 is the final velocity
[tex]a=-8.0 m/s^2[/tex] is the acceleration
Solving for u, we find the initial velocity:
[tex]u=\sqrt{v^2-2ad}=\sqrt{-2(8.0)(484)}=88 m/s[/tex]
