Answer:
45.06053 m/s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
g = Acceleration due to gravity = 9.81 m/s²
a = Acceleration
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow 0.809=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{0.809\times 2}{9.81}}\\\Rightarrow t=0.406\ s[/tex]
Time taken by the ball in the horizontal plane
Time = Distance / Speed
[tex]t=\frac{18.3}{u}[/tex]
[tex]s=\frac{1}{2}gt^2\\\Rightarrow 18.3=\frac{1}{2}\times 9.81\times \left(\frac{18.3}{u}\right)^2\\\Rightarrow u=\sqrt{\frac{1}{2}\times 9.81\times \frac{18.3^2}{0.809}}\\\Rightarrow u=45.06053\ m/s[/tex]
The Speed of the ball was 45.06053 m/s
