Answer: 3
Step-by-step explanation:
In theory we know that the equation of a linear function is expressed as
Eq.(1): y = m*x + c,
where m is the slope and c is a constant.
From the table we know the values of x and y, so we can use any of those, but in this case lets use the first and third rows of the table and substituting in Eq.(1) we obtain a 2-equation system as follow:
Point (-2,-2) gives: -2 = (-2)*m + c Eq.(2)
Point (0,4) gives: 4 = (0)*m + c Eq.(3)
Now rearranging Eq.(2) we get: -2 = -2*m + c <=> -2 - c = -2m Eq.(4)
Then rearranging Eq.(3) we get: 4 = 0 + c <=> c = 4
Plugging the value of c in Eq.(4) we get:
-2 = -2m + 4 <=> -2 - 4 = - 2m <=> -6 = -2m <=> m = 3
So finally and from Eq.(1) we obtain
y = 3x + c
