Two soccer players start from rest, 42 m apart. They run directly toward each other, both players accelerating. The first player’s acceleration has a magnitude of 0.60 m/s 2. The second player’s acceleration has a magnitude of 0.45 m/s2. (a) How much time passes before the players collide

Respuesta :

Answer:

8.94 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow s_1=0t+\frac{1}{2}\times 0.6\times t^2\\\Rightarrow s_1=0.3t^2[/tex]

[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow s_2=0t+\frac{1}{2}\times 0.45\times t^2\\\Rightarrow s_2=0.225t^2[/tex]

They both will run for the same amount of time assuming that they started running at the same time and together they will travel 42 m.

[tex]42=0.3t^2+0.225t^2\\\Rightarrow t=\sqrt{\frac{42}{0.3+0.225}}\\\Rightarrow t=8.94\ s[/tex]

The time at which they will collide is 8.94 seconds