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Draw all the isomers that have molecular formula C5H11Br. (Hint: There are eight.) Give the systematic name for each of the isomers. Give a common name for each isomer that has a common name. How many of the isomers are primary alkyl halides? How many of the isomers are secondary alkyl halides? How many of the isomers are tertiary alkyl halides?

Respuesta :

Answer:

The 8 isomers are drawn in the image:

1) 1-bromopentane

2) 2-bromopentane

3) 3-bromopentane

4) 1-bromo-2-methylbutane

5) 1-bromo-3-methylbutane

6) 2-bromo-2-methylbutane

7) 2-bromo-3-methylbutane

8) 1-bromo-2,2-dimethylpropane

1), 4), 5) and 8) are primary alkyl halides (alkyl bromides).

2), 3) and 7) are secondary alkyl halides (alkyl bromides).

6) is a tertiary alkyl halide (alkyl bromide).

Explanation:

Primary alkyl halides have the halogen (bromine) attached to a primary carbon, that is, a carbon that is attached to a single carbon (and two hydrogens).

Secondary halides have the halogen (bromine) attached to a secondary carbon, that is, a carbon that is attached to two carbons (and a hydrogen).

Tertiary halides have the halogen (bromine) attached to a tertiary carbon, that is, a carbon that is bonded to three carbons (and no hydrogen).

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