A quality control chemist at Dow Chemical tried to determine purity of NaOH using titration. He measured out 0.500 g NaOH sample and dissolved it in 20 mL water. 22.5 mL of a 0.500 mol/L HCl solution was used to reach the end point. Assume the impurity did not react with HCl, what is the % purity of this NaOH sample?

Respuesta :

Answer:

89.94 %

Explanation:

Considering:

[tex]Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}[/tex]

Or,

[tex]Moles =Molarity \times {Volume\ of\ the\ solution}[/tex]

Given :

For HCl :

Molarity = 0.500 M

Volume = 22.5 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 22.5×10⁻³ L

Thus, moles of HCl :

[tex]Moles=0.500 \times {22.5\times 10^{-3}}\ moles[/tex]

Moles of HCl = 0.01125 moles

The reaction of NaOH and HCl is:

NaOH + HCl ⇒ NaCl + H₂O

Moles of HCl = Moles of NaOH

Thus, Moles of NaOH = 0.01125 moles

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]

Thus,

[tex]0.01125\ moles= \frac{Mass}{39.997\ g/mol}[/tex]

[tex]Mass of NaOH= 0.4497\ g[/tex]

Total mass = 0.500 g

% purity = ( 0.4497 / 0.500 ) × 100 = 89.94 %

The study of chemicals and bonds is called chemistry. There are different types of elements and these are metals and nonmetals.

The correct answer is 0.500g.

What is titration?

  • Titration is a common laboratory method of quantitative chemical analysis to determine the concentration of an identified analyte
  • A reagent termed the titrant or titrator is prepared as a standard solution of known concentration and volume.
  • The titrant reacts with a solution of analyte to determine the analyte's concentration.

According to the question, the formula is used to solve the question is as follows:-

[tex]moles= molarity* volume[/tex]

The data is given as follows:-

  • Molarity = 0.500 M
  • Volume = 22.5 mL

Hence, the moles will be:-

[tex]0.500*22.5*10^{-3}[/tex] = 0.011225

The reaction of NaOH and HCl is:

[tex]NaOH + HCl ----> NaCl + H_2O[/tex]

  • Moles of HCl = Moles of NaOH

Thus, the mass of the NaOH

[tex]mass = 0.1125*39.997 \\=0.500g[/tex]

Hence, the correct answer is 0.500g.

For more information about the moles, refer to the link:-

https://brainly.in/question/9531558