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A chemist needs to know the concentration of some NaOH that is in the laboratory. To find this out, she titrates a 50.0 mL sample of the solution with 3.5 M HCl. If it takes 34.3 mL of the HCl to reach the titration endpoint, what is the concentration of the NaOH solution?

Respuesta :

Answer: 2.4 M

Explanation:

According to the neutralization law,

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of [tex]Hl[/tex] solution = 3.5 M

[tex]V_1[/tex] = volume of [tex]HCl[/tex] solution = 34.3 ml

[tex]M_2[/tex] = molarity of [tex]NaOH[/tex] solution = ?

[tex]V_2[/tex] = volume of [tex]NaOH[/tex] solution = 50 ml

[tex]n_1[/tex] = valency of [tex]HCl[/tex] = 1

[tex]n_2[/tex] = valency of [tex]NaOH[/tex] = 1

[tex]1\times 3.5M\times 34.3=1\times M_2\times 50[/tex]

[tex]M_2=2.4[/tex]

Therefore, the concentration of NaOH solution is 2.4 M.

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