Answer:
0.034%
Explanation:
First, let's calculated the average density (da) of the two experimental, which the sum of them divided by 2:
[tex]da = \frac{1.112x10^{-3} + 1.069x10^{-3}}{2}[/tex]
da = 1.090x10⁻³ g/cm³
The relative error is given by the difference of the correct value and the avarege, divided by the correct value:
[tex]e = \frac{1.429x10^{-3} - 1.090x10^{-3}}{1.429x10^{-3}}[/tex]
e = 3.39x10⁻⁴ x 100%
e = 0.034%
