Each leg of a 45°-45°-90° triangle measures 12 cm. Triangle X Y Z is shown. Angle X Y Z is a right angle and angles Y Z X and Z X Y are 45 degrees. The lengths of sides Z Y and Y X are 12 centimeters. What is the length of the hypotenuse? 6 cm 6 StartRoot 2 EndRoot cm 12 cm 12 StartRoot 2 EndRoot cm

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Answer:

[tex]XZ=12\sqrt{2}\ cm[/tex]

Step-by-step explanation:

Pythagorean theorem: In a right triangle with legs a, b and hypotenuse c,

[tex]a^2+b^2=c^2[/tex]

Given: ΔXYZ is right triangle with right angle Y.

Angles YZX and ZXY are 45 degrees.

ZY = YX = 12 cm

Find: XZ

Solution:

By the Pythagorean theorem,

[tex]XZ^2=XY^2+YZ^2\\ \\XZ^2=12^2+12^2\\ \\XZ^2=144+144\\ \\XZ^2=2\cdot 144\\ \\XZ=12\sqrt{2}\ cm[/tex]

The length of the hypotenuse is [tex]12\sqrt{2}[/tex] cm and this can be determined by using the Pythagorean theorem.

Given :

  • Each leg of a 45°-45°-90° triangle measures 12 cm.
  • Angle XYZ is a right angle and angles YZX and ZXY are 45 degrees.
  • The lengths of sides ZY and YX are 12 centimeters.

The length of the hypotenuse can be determined by using the Pythagorean theorem. According to this theorem, the square of the longer side is equal to the sum of the square of the shorter sides.

[tex]\rm H^2=P^2+B^2[/tex]  ---- (1)

where H is the hypotenuse, B is the base and P is the perpendicular.

Now, put the value of P and B in equation (1).

[tex]\rm (XZ)^2 = (ZY)^2+(YX)^2[/tex]

[tex]\rm (XZ)^2 = (12)^2+(12)^2[/tex]

[tex]\rm (XZ)^2 = 2\times 144[/tex]

[tex]\rm XZ = \sqrt{288}[/tex]

[tex]\rm XZ = 12\sqrt{2}\; cm[/tex]

For more information, refer to the link given below:

https://brainly.com/question/18163189