An art teacher has 47 1/3 pounds id clay. He wants to give each student in his class 2 1/2 pounds of clay. The teacher estimates that he has enough clay for 9 students. Is this the best estimate? Explain

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Answer:

See explanation

Step-by-step explanation:

An art teacher has [tex]47\frac{1}{3}[/tex] pounds of clay.

He wants to give each student in his class [tex]2\frac{1}{2}[/tex] pounds of clay.

To estimate how many student the teacher can give  [tex]2\frac{1}{2}[/tex] pounds of clay, just divide the whole amount of clay by  [tex]2\frac{1}{2}:[/tex]

[tex]47\dfrac{1}{3}=\dfrac{47\cdot 3+1}{3}=\dfrac{142}{3}\\ \\2\dfrac{1}{2}=\dfrac{2\cdot 2+1}{2}=\dfrac{5}{2}\\ \\47\dfrac{1}{3}:2\dfrac{1}{2}=\dfrac{142}{3}:\dfrac{5}{2}=\dfrac{142}{3}\cdot \dfrac{2}{5}=\dfrac{142\cdot 2}{3\cdot 5}=\dfrac{284}{15}\\ \\\dfrac{284}{15}=\dfrac{270+14}{15}=\dfrac{18\cdot 15+14}{15}=18\dfrac{14}{15}[/tex]

This means 18 students can get [tex]2\frac{1}{2}[/tex] pounds of clay. Thus, the teacher estimation is not the best estimate.