Answer:
[tex]\large\boxed{x=\dfrac{4}{7}}[/tex]
Step-by-step explanation:
[tex]6-\dfrac{2}{3}(x+5)=4x\qquad\text{multiply both sides by 3}\\\\(3)(6)-3\!\!\!\!\diagup\cdot\dfrac{2}{3\!\!\!\!\diagup}(x+5)=(3)(4x)\\\\18-2(x+5)=12x\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\18+(-2)(x)+(-2)(5)=12x\\\\18-2x-10=12x\qquad\text{cobmine like terms}\\\\-2x+(18-10)=12x\\\\-2x+8=12x\qquad\text{subtract 8 from both sides}\\\\-2x+8-8=12x-8\\\\-2x=12x-8\qquad\text{subtract}\ 12x\ \text{from both sides}\\\\-2x-12x=12x-12x-8\\\\-14x=-8\qquad\text{divide both sides by (-14)}\\\\\dfrac{-14x}{-14}=\dfrac{-8}{-14}\\\\x=\dfrac{8:2}{14:2}\\\\x=\dfrac{4}{7}[/tex]
