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A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 780 N on him. The mass of the losing player plus equipment is 86 kg, and he is accelerating at 2.6 m/s2 backward. Randomized Variables f = 780 N m1 = 86 kg m2 = 118 kg a = 2.6 m/s2 show answer No Attempt 50% Part (a) What is the magnitude of the force of friction, in newtons, between the losing player's feet and the grass as he slides backwards?

Respuesta :

Answer:

[tex]f = 556.4 N[/tex]

Explanation:

Mass of the losing player with its all equipment is given as

M = 86 kg

Net force applied on him by another player is given as

F = 780 N

also we know that acceleration of the losing player is given as

[tex]a = 2.6 m/s^2[/tex]

now by Newton's 2nd law we will have

[tex]F - f = ma[/tex]

[tex]780 - f = 86(2.6)[/tex]

[tex]780 - f = 223.6 [/tex]

[tex]f = 556.4 N[/tex]

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