Answer:
[tex]RCOO^{-}\\RNH_{2}\\H_{2}PO_{4}^{-}\\HCO_{3-}[/tex]
Explanation:
A conjugate base is formed when an acid in reaction with a base lose a proton H+.
For example if RCOOH that is an acid, reacts with water that is a base, the RCOOH loses an H+ and it becomes [tex]RCOO^{-}[/tex] that is the conjugate base; and the water gains the H+ and become the conjugate acid, that is:
* [tex]RCOOH, RCOO-[/tex]
[tex]RCOOH+H_{2}O=H_{3}O^{+}+RCOO^{-}[/tex]
The RCOO- is the conjugate base
* [tex]RNH_{2}, RNH_{3}^{+}[/tex]
[tex]RNH_{3}^{+}+H_{2}O=H_{3}O^{+}+RNH_{2}[/tex]
In this case the [tex]RNH_{2}[/tex] is the conjugate base
* [tex]H_{3}PO_{4},H_{2}PO_{4}^{-}[/tex]
[tex]H_{3}PO_{4}+H_{2}O=H_{3}O^{+}+H_{2}PO_{4}^{-}[/tex]
The [tex]H_{2}PO_{4}^{-}[/tex] is the conjugate base
* [tex]H_{2}CO_{3},HCO_{3}^{-}[/tex]
[tex]H_{2}CO_{3}+H_{2}O=H_{3}O^{+}+HCO_{3}^{-}[/tex]
The [tex]HCO_{3}^{-}[/tex] is the conjugate base.
