Answer:
43.868 J
Explanation:
Kinetic energy of a body is the amount of energy possessed by a moving body. The SI unit of kinetic energy is the joule (kg⋅m²⋅s⁻²).
According to classical mechanics, kinetic energy = 1/2 m·v²
Where, m= mass in kg and v= velocity in m/s
Given: m = 19.2 lb and v = 7.10 miles/h
Since, 1 lb= 0.453592 kg
∴ m = 19.2 lb = 19.2 × 0.453592 kg = 8.709 kg
Also, 1 mi = 1609.34 m and 1 h = 3600 sec
∴ v = 7.10 mi/h = 7.10 × 1609.34 m ÷ 3600 sec = 3.174 m/sec
Therefore, kinetic energy of the goose = 1/2 m·v² = 1/2 × (8.709 kg)× (3.174 m/sec)² = 43.868 J
The kinetic energy of the goose of mass 19.2 lb flying at 7.10 mph is 48.868 J
1 lb = 0.453592 Kg
Therefore,
19.2 lb = 19.2 × 0.453592
1 mph = 0.44704 m/s
Therefore,
7.10 mph = 7.10 × 0.44704
Mass (m) = 8.709 Kg
Velocity (v) = 3.174 m/s
KE = ½mv²
KE = ½ × 8.709 × 3.174²
Therefore, the kinetic energy of the goose is 48.868 J
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