A pycnometer is a precisely weighted vessel that is used for highly accurate density determinations. Suppose that a pycnometer has a mass of 27.60 g when it is empty and has a mass of 45.65 g when it is completely filled with water at 20 °C. A 9.5 g metal ingot is placed in the pycnometer. When it is then filled with water at 20 °C, the total mass is 56.83 g. If the density of water at 20 °C is 998.2 kg/m3, what is the density of the metal ingot in grams per cubic centimeter.

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Tringa0 Tringa0 · Answer 1 · 2019-10-03T09:17:46+02:00

Answer:

5.758 is the density of the metal ingot in grams per cubic centimeter.

Explanation:

1) Mass of pycnometer = M = 27.60 g

Mass of pycnometer with water ,m= 45.65 g

Density of water at 20 °C = d =[tex]998.2 kg/m^3[/tex]

1 kg = 1000 g

[tex]1 m^3=10^6 cm^3[/tex]

[tex]998.2 kg/m^3=\frac{998.2 \times 1000 g}{10^6 cm^3}=0.9982 g/cm^3[/tex]

Mass of water ,m'= m - M = 45.65 g - 27.60 g =18.05 g

Volume of pycnometer = Volume of water present in it = V

[tex]Density=\frac{Mass}{Volume}[/tex]

[tex]V=\frac{m'}{d}=\frac{18.05 g}{0.9982 g/cm^3}=18.08 cm^3[/tex]

2) Mass of metal , water and pycnometer = 56.83 g

Mass of metal,M' = 9.5 g

Mass of water when metal and water are together ,m''= 56.83 g - M'- M

56.83 g - 9.5 g - 27.60 g = 19.7 g

Volume of water when metal and water are together = v

[tex]v=\frac{m''}{d}=\frac{19.7 g}{0.9982 g/cm^3}=19.73 cm^3[/tex]

Density of metal = d'

Volume of metal = v' =[tex]\frac{M'}{d'}[/tex]

Difference in volume will give volume of metal ingot.

v' = v - V

[tex]v'=19.73 cm^3-18.08 cm^3=[/tex]

[tex]v'=1.65 cm^3[/tex]

Since volume cannot be in negative .

Density of the metal =d'

=[tex]d'=\frac{M'}{v'}=\frac{9.5 g}{1.65 cm^3}=5.758 g/cm^3[/tex]