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A football player kicks a ball with an initial
velocity of 25 meters per second at an angle of
53° above the horizontal. The vertical component
of the initial velocity of the ball is
A.
25 m/s
B,
D.
20. m/s
10. m/s
C.
15 m/s

Respuesta :

skyluke89

Answer:

20 m/s

Explanation:

The vertical component of the initial velocity of the ball is given by:

[tex]v_y = v_0 sin \theta[/tex]

where:

[tex]v_0[/tex] is the initial speed

[tex]\theta[/tex] is the angle of launch above the horizontal

In the problem we have

[tex]v_0 =25 m/s\\\theta=53^{\circ}[/tex]

Substituting into the equation,

[tex]v_y = (25)(sin 53^{\circ})=20 m/s[/tex]

snehashish65

Answer:

The vertical component  of the initial velocity of the ball is 20 m/s.

Explanation:

Given data:

Initial velocity is, u = 25 m/s.

Angle of inclination is, [tex]\theta = 53 ^{\circ}[/tex].

The vertical component of initial velocity is,

[tex]v = usin \theta[/tex]

Solving as,

[tex]v = 25 \times sin53\\v \approx 20 \;\rm m/s[/tex]

Thus, vertical component  of the initial velocity of the ball is 20 m/s.

For more details, refer the link:

https://brainly.com/question/13639113?referrer=searchResults

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