contestada

Consider the following reversible reaction.
C(s)+O2(g)<—>CO2(g)
What is the equilibrium constant expression for the given system?
[CO]
[CO]
[CO]

Respuesta :

znk

Answer:

Here's what I get.  

Explanation:

[tex]\rm C(s) + O_{2}(g) \rightleftharpoons CO_{2}(g)[/tex]

The general formula for an equilibrium constant expression is

[tex]K_{eq} = \dfrac{[\text{Products}]}{[\text{Reactants}]}[/tex]

For this reaction,  

[tex]K_{eq} = \dfrac{[\text{CO}_{2}]} {[\text{O}_{2}]}[/tex]

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