Answer:
[tex]\large \boxed{0.167}[/tex]
Explanation:
The mole fraction (χ) is the number of moles of a component divided by the total number of moles in a mixture.
[tex]\chi = \dfrac{\text{Moles of component}}{\text{ Total moles}}[/tex]
Let water = Component 1 and NaOH = component 2.
1. Calculate the total moles.
n₁ = 25.0 mol
n₂ = 5.0 mol
[tex]\begin{array}{rcl}n_{\text{tot} & = & 25.0 + 5.0\\& = & 30.0\\\end{array}[/tex]
2. Calculate the mole fraction of NaOH
[tex]\begin{array}{rcl}\chi_{2} & = &\dfrac{n_{2}}{n_{\text{tot}}}\\\\& = & \dfrac{5.0}{30.0}\\\\& = & \mathbf{0.167}\\\end{array}\\\text{The mole fraction of NaOH is $\large \boxed{\mathbf{0.167}}$}[/tex]
The mole fraction of sodium hydroxide will be 0.167.
The quantity of a particular element in the solution divided mostly by an overall fraction of moles with in sample solution often known as the mole fraction.
Formula of mole fraction is shown as:
Mole fraction = Moles of component / total moles
Given data:
[tex]n_{1} = 25 mol[/tex]
[tex]n_{2} = 5 mol[/tex]
Calculation of mole fraction
Total moles = [tex]n_{1} + n_{2} = 25 + 5 = 30 mol[/tex]
Now, put the values of given data in above equation
[tex]x_{2} = n_{2} / m_{total} \\x_{2} = 5/30\\x_{2} = 0.167[/tex]
Therefore, the mole fraction of NaOH will be 0.167.
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