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A package is dropped from a hovering helicopter.

If it takes 15.0s before the package strikes the ground, how high above the ground was the package when it was released?(Neglect air resistance and weight if the package)

Respuesta :

MathPhys

Answer:

1100 m

Explanation:

Given:

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

t = 15.0 s

Find: y₀

y = y₀ + v₀ t + ½ at²

0 m = y₀ + (0 m/s) (15.0 s) + ½ (-9.8 m/s²) (15.0 s)²

y₀ ≈ 1100 m

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