Answer:2584.52 mm
Explanation:
Given
Velocity is given=436-15t
V is in mm/s
and we know [tex]\frac{\mathrm{d} x}{\mathrm{d} t}=v[/tex]
[tex]\frac{\mathrm{d} x}{\mathrm{d} t}=436-15t[/tex]
[tex]dx=\left ( 436-15t\right )dt[/tex]
Integrating both sides we get
[tex]\int_{0}^{x}dx=\int_{0}^{6.7}\left ( 436-15t\right )dt[/tex]
[tex]x=\left ( 436t-15\cdot \frac{t^2}{2}\right )_0^{6.7}[/tex]
x=2584.52 mm
Here distance is equal to displacement because from graph area under the v -t graph gives displacement when we consider sign and distance if we take absolute values
