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A flowrate measuring device is installed in a horizontal pipe through which water is flowing. A U-tube manometer is connected to the pipe through pressure taps located 3 in. on either side of the device. The gage fluid in the manometer has a specific weight of 112 lb/ft3. Determine the differential reading of the manometer corresponding to a pressure drop between the taps of 0.5 lb/in2.

Respuesta :

Answer:

h=1.5 ft

Explanation:

Specific weight for manometer

[tex]W=112\ lb/ft^3[/tex]

Pressure drop between taps

[tex]\Delta P=0.5\ lb/in^2[/tex]

[tex]\Delta P=0.5\times 12^2\ lb/ft^2[/tex]

[tex]\Delta P=72\ lb/ft^2[/tex]

So

[tex]\Delta P=(\rho_m-\rho_w)gh[/tex]

[tex]\Delta P=(W_m-W_w)h[/tex]

We know that for water

[tex]W_w=64\ lb/ft^3[/tex]

Now by putting the values

[tex]\Delta P=(W_m-W_w)h[/tex]

[tex]72=(112-64)h[/tex]

h=1.5 ft

So reading of manometer is 1.5 ft.

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