Answer:
Explanation:
We know that the square modulus of the wavefunction integrated over a volume gives us the probability of finding the particle in that volume. So the result of the integral
[tex]\int\limits^{x_f}_{x_0} \int\limits^{yf}_{y_0} \int\limits^{z_f}_{z_0} |\psi|^2 \, dz \, dy \, dx[/tex]
must be dimensionless, as represents a probability.
As the differentials has units of length
[tex][dx]=[dy]=[dz]=[Length][/tex]
for the integral to be dimensionless, the units of the square modulus of the wavefunction has to be:
[tex][\psi]^2 = [Length^{-3}][/tex]
taking the square root this gives us :
[tex][\psi] = [Length^{-3/2}][/tex]
