A system undergoes a change such that the pressure changes from 0.36 atm to 0.34 atm and the volume changes from 8 L to 19 L. Simultaneously. Δυ-358 J. What is ΔΗ in Joules?

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Respuesta :

Alleei Alleei · Answer 1 · 2019-10-04T11:18:58+02:00

Answer : The value of [tex]\Delta H[/tex] is 4.76 J

Explanation :

Formula used :

[tex]\Delta H=\Delta U+\Delta n_g\times RT[/tex]

According to the ideal gas equation,

[tex]PV=nRT\\\\\Delta(PV)=\Delta n_gRT[/tex]

So,

[tex]\Delta H=\Delta U+\Delta (PV)[/tex]

[tex]\Delta H=\Delta U+(P_2V_2-P_1V_1)[/tex]

where,

[tex]\Delta U[/tex] = internal energy of the reaction = -358 J

[tex]\Delta H[/tex] = enthalpy of the reaction = ?

[tex]P_1[/tex] = initial pressure = 0.36 atm

[tex]P_2[/tex] = final pressure = 0.34 atm

[tex]V_1[/tex] = initial volume = 8 L

[tex]V_2[/tex] = final volume = 19 L

Now put all the given values in the above formula, we get:

[tex]\Delta H=\Delta U+(P_2V_2-P_1V_1)[/tex]

[tex]\Delta H=(-358J)+(0.34\times 19-0.36\times 8)L.atm[/tex]

[tex]\Delta H=(-358J)+3.58L.atm[/tex]

conversion used : [tex]1L.atm=101.33J[/tex]

[tex]\Delta H=(-358J)+3.58\times 101.33J[/tex]

[tex]\Delta H=4.76J[/tex]

Therefore, the value of [tex]\Delta H[/tex] is 4.76 J