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A jet plane that has a minimum takeoff speed of 80 m/s begins 70 m from one end of the runway. The runway is 2200 m long. What acceleration must it have to takeoff with 100 m to spare on the other end of the runway?

Respuesta :

Answer:

acceleration a = 1,557 m/s²

Explanation:

Let's use the kinematic equations, the initial distance is 70 m (Xo = 70 m), also if the track is 2200m long or 100m long when clearing use a distance in the path of

     X = 2200-100-70 = 2030 m

With this data let's calculate the acceleration

    Vf² = Vo² + 2 a X

the jet leaves the rest (Vo=0=

    a = Vf2 / 2X

    a = 80 2/2 2030

    a = 1,557 m/s²

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