Answer:
The magnitude of the acceleration of the elevator is 0.422 m/s²
Explanation:
The weight of the person is mass × acceleration of gravity
→ His mass = 45 kg , acceleration of gravity = 9.8 m/s²
→ The weight of the person = 45 × 9.8 = 441 N
The weight acting down ward
The scale reads 460 N
According to Newton's law:
→ ∑ forces in direction of motion = mass × acceleration
→ ∑ forces = 460 - 441 = 19 N
→ mass = 45 kg , acceleration = ?
Substitute the values in the rule above
→ 19 = 45 × acceleration
Divide both sides by 45
→ acceleration = 0.422 m/s²
The magnitude of the acceleration of the elevator is 0.422 m/s²
Answer:
[tex]10.22m/s^2[/tex]
Explanation:
We can find the answer using Newton's second law, which is expressed as follows:
[tex]F=ma[/tex]
Where [tex]F[/tex] is the force (in Newtons), [tex]m[/tex] is the mass (in kilograms) and [tex]a[/tex] is the acceleration (in [tex]m/s^2[/tex]).
Since we are asked for the acceleration, we clear for [tex]a[/tex] in the last equation:
[tex]a=\frac{F}{m}[/tex]
and we already have the values for the force and the mass: [tex]F=460N[/tex], [tex]m=45kg[/tex]
so we substitute them in the equation:
[tex]a=\frac{460N}{45kg} =10.22m/s^2[/tex]
The acceleration of the elevator is [tex]10.22m/s^2[/tex]
