Answer:
t = 1.66 seconds
Explanation:
Initial velocity of the football, u = 22.2 m/s
Angle above the horizontal, [tex]\theta=31^{\circ}[/tex]
Let [tex]v_y[/tex] is the vertical component of the velocity,
[tex]u_y=u\ sin\theta[/tex]
[tex]u_y=22.2\ sin(31)=11.43\ m/s[/tex]
Let t is the time for which the football in the air before it hits the ground. It can be calculated as :
[tex]v=u_y-gt[/tex]
v = 0
[tex]u_y=gt[/tex]
[tex]t=\dfrac{u_y}{g}[/tex]
[tex]t=\dfrac{11.43}{9.8}[/tex]
t = 1.66 seconds
Hence, this is the required solution.
