Answer:
Number of protons = [tex]2.3836\times 10^{26}[/tex]
Number of electrons = [tex]2.3836\times 10^{26}[/tex]
Charge on these electrons = -[tex]3.8185\times 10^{7}\ C[/tex]
Explanation:
1 atom of lead contains 82 protons and 82 electrons
1 mole = [tex]6.023\times 10^{23}[/tex] atoms
Thus,
1 mole of lead contains [tex]82\times 6.023\times 10^{23}[/tex] protons
Also, 1 mole of lead weighs 207.2 g
So,
207.2 g of lead contains [tex]82\times 6.023\times 10^{23}[/tex] protons
1 kg = 1000 g
So,
1000 g or 1 kg of lead contains [tex]\frac {82\times 6.023\times 10^{23}}{207.2}\times 1000[/tex] protons
Number of protons = [tex]2.3836\times 10^{26}[/tex]
Also, for neutral atom, number of protons = number of electrons.
Thus,
Number of electrons = [tex]2.3836\times 10^{26}[/tex]
Also,
Charge of 1 electron = - [tex]1.602\times 10^{-19}\ C[/tex]
Charge on these electrons = -[tex]2.3836\times 10^{26}\times 1.602\times 10^{-19}\ C[/tex]
Charge on these electrons = -[tex]3.8185\times 10^{7}\ C[/tex]
