A reconnaissance plane flies 605 km away from
its base at 284 m/s, then flies back to its base
at 426 m/s.
What is its average speed?
Answer in units of m/s.

Respuesta :

Answer:

                      [tex]v_{avg}  =[/tex] 355 m/s  

Explanation:

Distance = 605 km

Initial speed = [tex]v_{i}[/tex] = 284 m/s

Final velocity = [tex]v_{f}[/tex] = 426 m/s

Average speed = ?

There is two method two find average speed. In first method, using 3rd equation of motion, we find acceleration.

                        [tex]2as = v_{f}^{2}+v_{i}^{2}[/tex]

Then using first equation of motion, we find time

                        [tex]v_{f} = v_{i}+at[/tex]

Then using the formula of average velocity, we find average velocity

                         [tex]v_{avg}=\frac{total-distance}{total-time}[/tex]

Second method is very simple

                                  [tex]v_{avg}=\frac{v_{f}+v_{i} }{2}[/tex]

                                   [tex]v_{avg}=\frac{426+284}{2}[/tex]

                                   [tex]v_{avg}  =[/tex] 355 m/s