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A car is moving at 10 m/s to the right. It accelerates for 10 s after which it is moving at 5 m/s to the left. What was the car's acceleration during the 10 s interval? (a)-1.5 m/s^2 (b) -0.5 m/s^2 (c) 9.8 m/s^2 (d) 0.5 m/s^2 (e) 1.5 m/s^2

Respuesta :

Answer:

Acceleration, [tex]a=-1.5\ m/s^2[/tex]

Explanation:

It is given that,

Initial velocity of the car, u = 10 m/s (in right)

Final velocity of the car, v = -5 m/s (in left)  

Time taken, t = 10 s

Let a is the acceleration of the car. It can be calculated using the equation of kinematics. The equation is as :

[tex]v=u+at[/tex]

[tex]a=\dfrac{v-u}{t}[/tex]

[tex]a=\dfrac{-5-10}{10}[/tex]    

[tex]a=-1.5\ m/s^2[/tex]

So, the acceleration of the car is [tex]-1.5\ m/s^2[/tex]. Hence, this is the required solution.

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