Answer:0.846 c, 0
Explanation:
Giving
Body is initially moving with 0.5 c
The velocity of the fragment which is moving with velocity of 0.6 c is appears to be move with velocity of
[tex]v_0=\frac{u+v}{1+\frac{uv}{c^2}}[/tex]
[tex]v_0=\frac{0.5c+0.6c}{1+\frac{0.5c\cdot 0.6c}{c^2}}[/tex]
[tex]v_0=\frac{1.1c}{1.3}=0.846 c[/tex]
And the velocity of particle moving in opposite direction with velocity 0.5 c
[tex]v_0=\frac{u+v}{1+\frac{uv}{c^2}}[/tex]
[tex]v_0\frac{-0.5c+0.5c}{1+\frac{0.5c\times (-0.5c)}{c^2}}=0[/tex]
