Answer:
The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to - 2093 J.
Explanation:
Given data:
Mass of water = 50 g
Initial temperature= T1 = 20°C
Final temperature= T2 = 10°C
Specific heat of water= c = 4.186 J/g. °C
Amount of heat released = Q= ?
Solution:
Formula:
Q = m. C. ΔT
ΔT = T2 - T1
ΔT = 10°C - 20°C
ΔT = -10°C
Now we will put the values in formula.
Q = m. C. ΔT
Q = 50 g . 4.186 J/g. °C . -10°C
Q = - 2093 J
The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to - 2093 J.
The amount of heat energy released is -2092 J
From the question,
We are to determine the amount of heat energy released when 50.0 g of water is cooled from 20.0 °C to 10.0 °C
From the formula
Q = mcΔT
Where Q is the quantity of heat
m is the mass of substance
c is specific heat capacity of substance (c of water = 4.184 J/g °C)
ΔT is the change in temperature
From the given information
m = 50.0 g
ΔT = T₂ - T₁ = 10.0 °C - 20.0 °C
ΔT = -10.0 °C
Putting these values into the formula, we get
Q = 50.0 × 4.184 × -10.0
Q = -2092 J
Hence, the amount of heat energy released is -2092 J
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