ahawkins22
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In a floor plan, the length, l, of a rectangular room is twice its width, w. The perimeter of the room must be greater than 72 feet. Which inequality can be used to find all possible widths of the room, in feet? A. 6w > 72 B. 6w < 72 C. 3w > 72 D. 3w < 72

Respuesta :

carlosego

For this case we have that by definition, the perimeter of a rectangle is given by:

[tex]P = 2l + 2w[/tex]

Where:

l: It is the length of the rectangle

w: It is the width of the rectangle

According to the problem data we have:

[tex]l = 2w[/tex]

So, the perimeter of the plant is:

[tex]P = 2 (2w) + 2w = 4w + 2w = 6w[/tex]

If the perimeter must be greater than 72 feet, then we have:

[tex]6w> 72[/tex]

Thus, the inequality that can be used is[tex]6w> 72[/tex]

ANswer:

[tex]6w> 72[/tex]

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