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An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s1045 rad/s ). If a particular disk is spun at 264.9 rad/s264.9 rad/s while it is being read, and then is allowed to come to rest over 0.368 seconds0.368 seconds , what is the magnitude of the average angular acceleration of the disk?

Respuesta :

Answer:

719.84 rad/s²

Explanation:

Given that:

[tex]\omega_{initial}=264.9\ rad/s[/tex]

[tex]\omega_{final}=0\ rad/s[/tex] (Has to come to rest)

t = 0.368 seconds

Thus, the expression for angular expression is:-

[tex]\alpha=\frac{\omega_{final}-\omega_{initial}}{t}[/tex]

Applying the values in the above equation as:-

[tex]\alpha=\frac{\omega_{final}-\omega_{initial}}{t}\\\Rightarrow \alpha=\frac{0-264.9}{0.368}\\\Rightarrow \alpha=-719.84\ rad/s^2[/tex]

Magnitude of the average angular acceleration = 719.84 rad/s²

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