Answer:
44.1 m
Explanation:
The vertical motion of the projectile is a free fall motion, so it is a uniform accelerated motion. This means that we can use the suvat equation:
[tex]s=ut+\frac{1}{2}at^2[/tex]
where
, taking downward as positive direction:
s is the vertical displacement
u = 0 is the initial vertical velocity of the projectile (it is fired horizontally)
t is the time
[tex]a=g=9.8 m/s^2[/tex] is the acceleration of gravity
We know that the projectile hits the ground at
t = 3.0 s
Therefore, by substituting this value into the equation, we find the vertical displacement of the projectile at that time, that is equal to the height of the cliff:
[tex]s=0+\frac{1}{2}(9.8)(3)^2=44.1 m[/tex]
