Boron carbonate decomposes into boron oxide and carbon dioxide. How many moles of CO2
are produced when 5.0 mol of boron carbonate decomposes completely?
1 B2(CO3) - 1 B,0,3 CO,
O
A. 15 mol
OB. 1.67 mol
O
C. 5 mol
O D. 8 mol

Respuesta :

Answer:

15 moles

Explanation:

The decomposition of boron carbonate is given by the equation;

B₂(CO₃)₃(s) → B₂O₃(s) + 3CO₂(g)

Moles of boron carbonate decomposed is 5.0 mol

To find the moles of CO₂ produced we are going to use the mole ratio.

Mole ratio of B₂(CO₃)₃ to CO₂ is 1 : 3

Therefore;

Moles of CO₂ = Moles of B₂(CO₃)₃ × 3

                      = 15 mol

Therefore, 15 moles of CO₂ will be produced

   

15 moles of CO₂ are produced when 5.0 mol of boron carbonate decomposes completely.

What is decomposition reaction?

Decomposition reaction are those in which one reactant is decompose or breakdown into two or more products.

The reaction is

[tex]\rm B_2(CO_3)_3(s) = B_2O_3(s) + 3CO_2(g)[/tex]

Moles of boron carbonate is 5.0 mol

The mole ratio will be

[tex]\rm B_2(CO_3)_3 : CO_2[/tex]

             1 : 3

Therefore, the mole of CO₂ = mole of B₂(CO₃)₃ × 3 = 15 mol

Thus, the  correct option is A, 15 mol.

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