Answer:
Price of each phone: [tex]\$9[/tex]
Price of each accessory: [tex]\$3.5[/tex]
Step-by-step explanation:
Let be "p" the price in dollars of each phone and "a" the price in dollars of each accessory.
Set up a system of equations:
[tex]\left \{ {{8p+10a=107} \atop {4p+23a=116.50}} \right.[/tex]
You can use the Elimination Method to solve the system.
Multiply the second equation by -2 and add both equations:
[tex]\left \{ {{8p+10a=107} \atop {-8p-46a=-233}} \right.\\............................\\-36a=-126\\\\a=\frac{-126}{-36}\\\\a=3.5[/tex]
Substitute the value of "a" into the first equation and solve for "p":
[tex]8p+10(3.5)=107\\\\8p=107-35\\\\p=\frac{72}{8}\\\\p=9[/tex]
