The chart shows the distances and mirrors that three students ran over a 10 second period.


Which student ran the fastest?

A. Student 1

B. Student 2

C. Student 3

D . Student 1 and 2 tied for fastest

Please look at the image for the chart.

Please please please hurry I need this for a test please!!?!?!?!?!!?

The chart shows the distances and mirrors that three students ran over a 10 second period Which student ran the fastest A Student 1 B Student 2 C Student 3 D St class=

Respuesta :

Answer: C. Student 3

Explanation: don’t you see what you marked on YOUR screen

Answer : The correct option is, (C) Student 3

Explanation :

Speed : It is defined as the distance covered per unit of time.

Formula used :

[tex]Speed=\frac{Distance}{Time}[/tex]

From the given data we conclude that:

Speed of student 1, 2 and 3 at time 1 is:

[tex]S_1=\frac{1}{1}=1[/tex]

[tex]S_2=\frac{2}{1}=2[/tex]

[tex]S_3=\frac{4}{1}=4[/tex]

Speed of student 1, 2 and 3 at time 2 is:

[tex]S_1=\frac{2}{2}=1[/tex]

[tex]S_2=\frac{4}{2}=2[/tex]

[tex]S_3=\frac{8}{2}=4[/tex]

and so on.......

That means,

The speed of student 1 at time 1, 2, 3, 4, 5, 6, 7, 8, 9 and 10 is, 1

The speed of student 2 at time 1, 2, 3, 4, 5, 6, 7, 8, 9 and 10 is, 2

The speed of student 3 at time 1, 2, 3, 4, 5, 6, 7, 8, 9 and 10 is, 4

This means that, student 3 ran the fastest as student 2 and 1.