Answer:
0.136 C
Explanation:
This question uses the simple idea of conservation of energy. We work with the assumption that energy loss is zero
At the top of the waterfall the water has maximum potential energy
[tex]P_{e} = mgh[/tex]
Where
[tex]m[/tex] = Mass of water
[tex]g[/tex] = Acceleration due to gravity
[tex]h[/tex] = Height
Now at the bottom just before impact all of the potential energy is converted to kinetic energy and right after impact all this kinetic energy is converted to thermal energy ([tex]T_{e}[/tex])
[tex]T_{e} = mc_{w} (dT)[/tex]
Where
[tex]m[/tex] = Mass of water
[tex]c_{w}[/tex] = Specific Heat Capacity of Water
[tex]dT[/tex] = Change in Temperature
Equating the two equations
[tex]P_{e} = T_{e} \\ mgh = mc_{w}(dT)\\ gh = c_{w}(dT)\\ dT = \frac{gh}{c_{w}}[/tex]
Since the value of [tex]c_{w}[/tex] is a constant, it is equal to 4186 J / (kg * C). We input all the given values into the equation and find the answer
[tex]dT = \frac{(9.81)(58)}{4186}}\\ dT = 0.136 C[/tex]
