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A light, inextensible cord passes over a light, frictionless pulley with a radius of 15 cm. It has a(n) 12 kg mass on the left and a(n) 4.1 kg mass on the right, both hanging freely. Initially their center of masses are a vertical distance 3.3 m apart. The acceleration of gravity is 9.8 m/s 2 . 3.3 m 15 cm ω 12 kg 4.1 kg At what rate are the two masses accelerating when they pass each other? Answer in units of m/s 2 .

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Answer:

5.04m/s^2

Explanation:

We define the variables like this,

[tex]m_1 = 15Kg[/tex]

[tex]m_2 = 4.8Kg[/tex]

[tex]g= 9.8m/s^2[/tex]

[tex]a= Acceleration[/tex]

We know that the rate  is gived for the equation,

[tex]a = \frac{F_{net}}{m_{Total}}[/tex]

[tex]a= \frac{ ( m1 - m2 ) g}{ (m1 + m2 )}[/tex]

[tex]a= \frac {10.2 ( 9.8 )}{19.8} = 5.04m/s^2[/tex]

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