contestada

Four penguins that are being playfully pulled along very slippery (frictionless) ice by a curator. The masses of three penguins and the tension in two of the cords are 1 12 m kg = , 3 15 m kg = , 4 20 m kg = , 2 111TN= , 4 222TN= . Find the penguin mass 2m that is not given.

Respuesta :

Answer:

[tex]m_2 = 23 kg[/tex]

Explanation:

As we know that the tension in two strings are

[tex]T_2 = 111 N[/tex]

[tex]T_4 = 222 N[/tex]

now we have

[tex]F_{net} = ma[/tex]

so we can say

[tex](m_1 + m_2)a = T_2[/tex]

[tex](12 + m_2)a = 111[/tex]

also we have

[tex](m_1 + m_2 + m_3 + m_4) a = T_4[/tex]

[tex](12 + m_2 + 15 + 20) a = 222[/tex]

now divide two equations

[tex]\frac{222}{111} = \frac{47 + m_2}{12 + m_2}[/tex]

[tex]2m_2 + 24 = 47 + m_2[/tex]

[tex]m_2 = 23 kg[/tex]

Otras preguntas