Answer:
Step-by-step explanation:
n=175, p=0.53
q = 1–q = 1 – 0.53 = 0.47
Since np = (175)(0.53) = 92.75 and nq = (175)(0.47) = 82.25, the normal distribution can be used to
approximate the binomial distribution.
µ = np = (175)(0.53) = 92.75
σ = npq = (175)(0.53)(0.47) = 43.5925 = 6.60246
For binomial distribution, P(X > 75) and P(X < 110)
For normal distribution, P(75 + 0.5 < X < 110 – 0.5)
= P(75.5 < X < 109.5)
