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Two long parallel wires are a distance d apart ( d = 12 cm) and carry equal and opposite currents of 5.2 A. Point P is a distance d from each of the wires. Calculate the magnitude of the magnetic field strength (in Teslas) at point P. Count not copy the figure, The figure looks like this: P X o with equal distance d apart X means going in to the page o means coming out Please give exact answer

Respuesta :

Answer:

[tex]B_{net} = 8.67 \times 10^{-6} T[/tex]

Explanation:

As we know that the magnetic field is given as

[tex]B = \frac{\mu_0 i}{2\pi r}[/tex]

so here we know that

[tex]i = 5.2 A[/tex]

[tex]r = d = 12 cm[/tex]

now we have magnetic field given as

[tex]B = \frac{(2 \times 10^{-7})(5.2)}{0.12}[/tex]

[tex]B = 8.67 \times 10^{-6} T[/tex]

now net magnetic field at Point P is given as

[tex]B_{net} = 2Bcos60[/tex]

so we have

[tex]B_{net} = 2(8.67 \times 10^{-6})cos60[/tex]

[tex]B_{net} = 8.67 \times 10^{-6} T[/tex]

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