Answer:
the average of this new list of numbers is 94
Step-by-step explanation:
Hello!
To answer this question we will assign a letter to each number for the first list and the second list of numbers, remembering that the last number of the first list is 80 and the last number of the second list is 96
for the first list
[tex]\frac{a+b+c+80}{4} =90[/tex]
for the new list
[tex]\frac{a+b+c+96}{4} =X[/tex]
To solve this problem consider the following
1.X is the average value of the second list
2. We will assign a Y value to the sum of the numbers a, b, c.
a + b + c = Y to create two new equations
for the first list
[tex]\frac{y+80}{4} =90[/tex]
solving for Y
Y=(90)(4)-80=280
Y=280=a+b+c
for the second list
[tex]\frac{y+96}{4} =X\\[/tex]
[tex]\frac{280+96}{4} =X\\x=94[/tex]
the average of this new list of numbers is 94
Answer:average of new list is 94
Step-by-step explanation:
Average = sum of numbers/ total number of numbers
Let the original list contain x,y,z and 80
Average = 90
Numbers = 4
Average of original list
=(x+y+z+80)/4=90
x+y+z+80= 360
x+y+z=280
Let (x+y+z) = b
b = 280
The new list has 4 numbers and the same first 3 numbers as the original list, but the the fourth number in the new list is 96.
That means the sum of the first 3 numbers, (x+y+z) which equals b in the original list is same as the sum of the first 3 numbers in the new list
Let average of the new list be a
Average of new list
=(b +96 )/4 =a
b +96 = 4a
b = 4a-96
Since b in original list = b in new list
4a-96 = 280
4a = 280+96=376
a = 376/4 =94
