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A 1050 kg sports car is moving westbound at 15.0 m/s on a level road when it collides with a 6320 kg truck driving east on the same road at 14.0 m/s. The two vehicles remain locked together after the collision. What is the velocity (magnitude) of the two vehicles just after the collision (in m/s)?

Respuesta :

Answer:

The velocity of the two vehicles just after the colision is 6.44 m/s to the east.

Explanation:

Since the forces of the two vehicles are exerting on each other is very large, you can affirm that the external net force on the system is approximately zero and so the momentum is conserved. Moreover, because the two vehicles are still locked together after the collision, you can consider that they have the same final velocity:

VA2= VB2 = V2

mA, mB, VA1, and VB2, substituing for the equation 2:

(1050).(-15.0)+(6320).(10)= (1050). V2 +(6320). V2

V2= (1050). (-15.0)+ (6320).(10)

                1050+6320

V2 = 6,44 m/s to the east

Answer:velocity = 10 m/s

Explanation:

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