aldas7
contestada

Knowing that
[tex] \frac{x + y}{y} = 3[/tex]
solve these problems
a.
[tex] \frac{x}{y} [/tex]
b.
[tex] \frac{y}{x + y} [/tex]
c.
[tex] \frac{x - y}{y} [/tex]
d.
[tex] \frac{y}{x} [/tex]
​

Respuesta :

waqaskhan15836

Answer:

a. x/y = 2          b) y/x +y =1/3    c) x-y/y= 1     d) y/x = 1/2

Step-by-step explanation:

Solve for  

a) x/y

as we know x +y/y  = 3

 x+y= 3y  

x= 3y-y

x= y(3-1)

x/y= 3-1

x/y = 2

b)  y/x+y

as we know x +y/y  = 3

x+y = 3y

1= 3y/x+y

1/3 = y/x+y

So y/x +y =1/3

C) x-y /y

as we know x +y/y  = 3

x +y = 3y

subtracting 2y from both sides  

x +y -2y = 3y- 2y

x-y = y

dividing both sides by y

x-y/y = y/y

x-y/y= 1

d) y/x

as we know x +y/y  = 3

x +y = 3y

x= 3y- y

x= 2y

dividing both sides by x

x/x = 2y/2x

1 = 2 x (y/x)

1 / 2 = y/x

Or y/x = 1/2

Best of luck.

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