Which shows 42^2 − 38^2 being evaluated using the difference of perfect squares method?

A) 42^2 − 38^2 = (1,764 − 1,444)(1,764 + 1,444) = 1,026,560
B) 42^2 − 38^2 = 84 − 76 = 8
C) 42^2 − 38^2 = (42 − 38)^2 = (4)^2 = 16
D) 42^2 − 38^2 = (42 + 38)(42 − 38) = (80)(4) = 320

Respuesta :

Answer:

D

Step-by-step explanation:

a²  - b² ← is a difference of squares and is factored in general as

(a + b)(a - b)

42² - 38² ← is a difference of squares and factors as

42² - 38² = (42 + 38)(42 - 38) = 80(4) = 320 → D

The statement that shows that 42^2 − 38^2 has been evaluated using the difference in perfect squares method is = 42^2 − 38^2 = (42 + 38)(42 − 38) = (80)(4) = 320.

What is a perfect squares?

A perfect square is derived when an integer, which may be positive or negative, is multiplied by itself.

The difference of a perfect square is being calculated by addition of the two separate integers multiplied by its difference.

That is , (42 +38) (42 -38)

= 80 × 4

= 320

Therefore, the statement that shows that 42^2 − 38^2 has been evaluated using the difference in perfect squares method is = 42^2 − 38^2 = (42 + 38)(42 − 38) = (80)(4) = 320.

Learn more about perfect square here:

https://brainly.com/question/27307830

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