The probability of getting a total of 12 is 1/36
Further explanation:
When two fair-dices are rolled, and the total outcomes are 36.
Which means that our sample space has 36 elements
[tex]n(S)=36[/tex]
Let A be the event that the sum of both dice are 12
Only one outcome from the sample space sums up to 12
A = {(6,6)}
So,
[tex]n(A) = 1[/tex]
[tex]P(A)=\frac{n(A)}{n(S)}[/tex]
=1/36
The probability of getting a total of 12 is 1/36
Keywords: Theoretical probability, Dice probability
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