The return trip took 1 hour 42 minutes longer
Further explanation:
The distance will remain same on return.
The formula for speed is given by:
[tex]Speed=\frac{Distance}{Time}[/tex]
Let d be the distance
s1 be the speed while going and s2 be the speed while returning
and
t1 be the time while going and t2 be the time while returning
d=500 miles
s1=60 miles per hour
s2=50 miles per hour
We have to calculate time for both trips,
So,
Time while Going:
[tex]s_1=\frac{d}{t_1}\\t_1=\frac{d}{s_1}[/tex]
Putting the values of d and s1
[tex]t_1=\frac{500}{60}\\=8.3\ hours[/tex]
Converting 8.3
8 will be the hours,
for 0.3 hour
0.3*60=18 minutes
The first trip took 8 hours and 18 minutes.
Time while returning:
[tex]s_2=\frac{d}{t_2}\\t_2=\frac{d}{s_2}[/tex]
Putting the values of d and s1
[tex]t_2=\frac{500}{50}\\=10\ hours[/tex]
The difference of both times is: 1 hour 42 minutes
So,
The return trip took 1 hour 42 minutes longer
Keywords: Time, Distance, Speed
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