Three consecutive even integers have the property that when the difference between the first and twice the second is found, the result is eight more than the third. Find the three consecutive even integers

Respuesta :

Consecutive even integers are -8, -6 and -4

Step-by-step explanation:

Let  be the first even integer then the next two integers will be: x+2 and x+6

According to given property, we get

[tex]x - 2(x+2) = (x+4)+8\\x-2x-4 = x+4+8\\-x-4 = x+12\\-x-x = 12+4\\-2x = 16[/tex]

Dividing both sides by -2

[tex]\frac{-2x}{-2} = \frac{16}{-2}\\x = -8[/tex]

The two next integers are:

x+2 = -8+2 = -6

x+4 = -8+4 = -4

Verification:

[tex]-8-2(-6) = -4+8\\-8+12 = +4\\4 = 4[/tex]

Hence, Consecutive even integers are -8, -6 and -4

Keywords: Linear equation, Variables

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